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Sorting fractions
Sort the following fractions from greatest to smallest: $\dfrac{4}{3}, \dfrac{7}{9}, \dfrac{11}{8}, \dfrac{5}{6}$ and $1.$
We compare the fractions one by one.
- $\dfrac{4}{3}=\dfrac{12}{9}$ and then it $\dfrac{4}{3}$ is bigger than $\dfrac{7}{9}$.
- $\dfrac{4}{3}=\dfrac{32}{24}$ and $\dfrac{11}{8}=\dfrac{33}{24}$ then $\dfrac{4}{3}$ is less than $\dfrac{11}{8}$.
- $\dfrac{4}{3}=\dfrac{8}{6}$ and then $\dfrac{4}{3}$ is bigger than $\dfrac{5}{6}$.
- $1=\dfrac{3}{3}$ and then $\dfrac{4}{3}$ is bigger than $1$.
Then, the biggest is $\dfrac{11}{8}$ and the second biggest is $\dfrac{4}{3}$. We compare three remaining ones. $\dfrac{5}{6}=\dfrac{15}{18}$ and $\dfrac{7}{9}=\dfrac{14}{18}$, then $\dfrac{5}{6}$ is bigger than $\dfrac{7}{9}.$ $1=\dfrac{9}{9}$ and then $\dfrac{7}{9}$ is less than $1$.
In conclusion, sorted from greatest to smallest we have the fractions $\dfrac{7}{9}, \dfrac{5}{6}, 1, \dfrac{4}{3}$ and $\dfrac{11}{8}.$
Sorted from smallest to greatest we have the fractions $\dfrac{7}{9}, \dfrac{5}{6}, 1, \dfrac{4}{3}$ and $\dfrac{11}{8}.$