- Inicio
- Fraccions
- Nombres mixtos
- Ejercicios
Nombres mixtos
Resol i presenta en resultat en forma de nombre mixt:
- $5\dfrac{8}{9}+2\dfrac{7}{11}$
- $\dfrac{45}{8}-2\dfrac{1}{3}$
- $27\dfrac{1}{2}-\dfrac{84}{7}$
- $\dfrac{23}{3}+\dfrac{9}{5}$
- $5\dfrac{8}{9}+2\dfrac{7}{11}=(5+2)+\Big(\dfrac{8}{9}+\dfrac{7}{11}\Big)=$ $=7+\Big(\dfrac{8\cdot11}{9\cdot11}+\dfrac{7\cdot9}{11\cdot9}\Big)=7+\dfrac{88+63}{99}=7+\dfrac{151}{99}=$ $=7+1+\dfrac{52}{99}=8\dfrac{52}{99}$
- $\dfrac{45}{8}-2\dfrac{1}{3}=5\dfrac{5}{8}-2\dfrac{1}{3}=5-2+\Big(\dfrac{5}{8}-\dfrac{1}{3}\Big)=3+\dfrac{15-8}{24}=3+\dfrac{7}{24}=3\dfrac{7}{24}$
- $27\dfrac{1}{2}-\dfrac{84}{7}=27\dfrac{1}{2}-12=27-12+\dfrac{1}{2}=$ $15+\dfrac{1}{2}=15\dfrac{1}{2}$
- $\dfrac{23}{3}+\dfrac{9}{5}=7\dfrac{2}{3}+1\dfrac{4}{5}=(7+1)+\Big(\dfrac{2}{3}+\dfrac{4}{5}\Big)=$ $=8+\dfrac{10+12}{15}=8+\dfrac{22}{15}=8+1+\dfrac{7}{15}=9\dfrac{7}{15}$
- $8\dfrac{52}{99}$
- $3\dfrac{7}{24}$
- $15\dfrac{1}{2}$
- $9\dfrac{7}{15}$