Simplification in expressions with factorials

Calculate the value of: $\dfrac{8!\cdot3!}{9!\cdot4!}$

$$\dfrac{8!\cdot3!}{9!\cdot4!}=\dfrac{\cancel{8!}\cdot\cancel{3!}}{9\cdot\cancel{8!}\cdot4\cdot\cancel{3!}}=\dfrac{1}{9\cdot4}=\dfrac{1}{36}$$

$$\dfrac{1}{36}$$

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